Can you give the proof? If you can't show , and then I contruct
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c
-15少-
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06/01/2011 postreply
03:34:14
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What is relation? your 1 to 6 is just my proof. my 2011/2 out of
-jinjing-
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06/01/2011 postreply
06:51:04
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回複:What is relation? your 1 to 6 is just my proof. my 2011/2 out
-15少-
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06/01/2011 postreply
08:31:32
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your (2) means f is bijection function. 1 to 1 and onto.
-jinjing-
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06/01/2011 postreply
09:03:44
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回複:your (2) means f is bijection function. 1 to 1 and onto.
-15少-
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06/01/2011 postreply
09:19:59
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If f is linear, OK. But we can't say nonlinear f is impossible b
-jinjing-
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06/01/2011 postreply
11:41:54
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you said yourself "for any f, no solution"
-15少-
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06/01/2011 postreply
13:14:55
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回複:you said yourself "for any f, no solution"
-jinjing-
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06/01/2011 postreply
14:28:17
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is there anything wrong in my demonstration 1) to 6)?
-15少-
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06/01/2011 postreply
15:06:40
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your answer is not math answer, I do this Q, I hope you can see.
-jinjing-
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06/02/2011 postreply
10:07:19
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MY answer is MY math answer.
-15少-
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06/02/2011 postreply
12:41:02
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I like the people who like Math. Let me tell you the detail.
-jinjing-
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06/02/2011 postreply
15:51:05
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回複:I like math, not myth nor mystification
-15少-
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06/02/2011 postreply
17:24:06
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You at first you don't think f(N1)=N2,so,I ,,,,your deduce prove
-jinjing-
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06/02/2011 postreply
18:23:04
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Nice!
-亂彈-
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06/01/2011 postreply
18:40:26
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thanks!
-15少-
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06/02/2011 postreply
12:46:16
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回複:c Could you provide some details for
-wxcfan123-
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06/11/2011 postreply
18:57:48
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figure out missing details. Nice problem and nice solution.
-wxcfan123-
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06/12/2011 postreply
14:36:53