no such relation neither

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• Can you give the proof? If you can't show , and then I contruct -jinjing- ♀ (0 bytes) () 05/31/2011 postreply 18:10:49

• c -15少- ♂ (681 bytes) () 06/01/2011 postreply 03:34:14

• What is relation? your 1 to 6 is just my proof. my 2011/2 out of -jinjing- ♀ (255 bytes) () 06/01/2011 postreply 06:51:04

• 回複：What is relation? your 1 to 6 is just my proof. my 2011/2 out -15少- ♂ (133 bytes) () 06/01/2011 postreply 08:31:32

• your (2) means f is bijection function. 1 to 1 and onto. -jinjing- ♀ (78 bytes) () 06/01/2011 postreply 09:03:44

• 回複：your (2) means f is bijection function. 1 to 1 and onto. -15少- ♂ (47 bytes) () 06/01/2011 postreply 09:19:59

• If f is linear, OK. But we can't say nonlinear f is impossible b -jinjing- ♀ (45 bytes) () 06/01/2011 postreply 11:41:54

• you said yourself "for any f, no solution" -15少- ♂ (41 bytes) () 06/01/2011 postreply 13:14:55

• 回複：you said yourself "for any f, no solution" -jinjing- ♀ (55 bytes) () 06/01/2011 postreply 14:28:17

• is there anything wrong in my demonstration 1) to 6)? -15少- ♂ (0 bytes) () 06/01/2011 postreply 15:06:40

• your answer is not math answer, I do this Q, I hope you can see. -jinjing- ♀ (191 bytes) () 06/02/2011 postreply 10:07:19

• MY answer is MY math answer. -15少- ♂ (299 bytes) () 06/02/2011 postreply 12:41:02

• I like the people who like Math. Let me tell you the detail. -jinjing- ♀ (177 bytes) () 06/02/2011 postreply 15:51:05

• 回複：I like math, not myth nor mystification -15少- ♂ (266 bytes) () 06/02/2011 postreply 17:24:06

• You at first you don't think f(N1)=N2,so,I ,,,,your deduce prove -jinjing- ♀ (164 bytes) () 06/02/2011 postreply 18:23:04

• Nice! -亂彈- ♂ (0 bytes) () 06/01/2011 postreply 18:40:26

• thanks! -15少- ♂ (0 bytes) () 06/02/2011 postreply 12:46:16

• 回複：c Could you provide some details for -wxcfan123- ♂ (247 bytes) () 06/11/2011 postreply 18:57:48

• figure out missing details. Nice problem and nice solution. -wxcfan123- ♂ (335 bytes) () 06/12/2011 postreply 14:36:53