h = hight of the arc. and A = 2*Pi*R*h
L = tangent line. 2a = chord.
L^2 = r*(2R + r), a^2 = h*(2R - h), and substitue them in
(h + r)^2 = L^2 - a^2
h = Rr/(2(R+r)).
h = hight of the arc. and A = 2*Pi*R*h
L = tangent line. 2a = chord.
L^2 = r*(2R + r), a^2 = h*(2R - h), and substitue them in
(h + r)^2 = L^2 - a^2
h = Rr/(2(R+r)).
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You Rit. We also can use similar tringles and ...getting h(r-h)=
-jinjing-
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08/15/2011 postreply
16:44:33
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(R+r-h)^2=(R+r)^2-R^2-h^2,...
-jinjing-
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08/15/2011 postreply
17:31:02
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Sorry, It should be: (R+r-h)h=(R+r)^2-R^2-h^2,...
-jinjing-
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08/15/2011 postreply
17:33:49
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