h = hight of the arc. and A = 2*Pi*R*h
L = tangent line. 2a = chord.
L^2 = r*(2R + r), a^2 = h*(2R - h), and substitue them in
(h + r)^2 = L^2 - a^2
h = Rr/(2(R+r)).
h = hight of the arc. and A = 2*Pi*R*h
L = tangent line. 2a = chord.
L^2 = r*(2R + r), a^2 = h*(2R - h), and substitue them in
(h + r)^2 = L^2 - a^2
h = Rr/(2(R+r)).
• You Rit. We also can use similar tringles and ...getting h(r-h)= -jinjing- ♀ (0 bytes) () 08/15/2011 postreply 16:44:33
• (R+r-h)^2=(R+r)^2-R^2-h^2,... -jinjing- ♀ (0 bytes) () 08/15/2011 postreply 17:31:02
• Sorry, It should be: (R+r-h)h=(R+r)^2-R^2-h^2,... -jinjing- ♀ (0 bytes) () 08/15/2011 postreply 17:33:49