(R+r-h)^2=(R+r)^2-R^2-h^2,...
回答: You Rit. We also can use similar tringles and ...getting h(r-h)=
由 jinjing
於 2011-08-15 16:44:33
所有跟帖:
• Sorry, It should be: (R+r-h)h=(R+r)^2-R^2-h^2,... -jinjing- ♀ (0 bytes) () 08/15/2011 postreply 17:33:49