(R+r-h)^2=(R+r)^2-R^2-h^2,...
回答: You Rit. We also can use similar tringles and ...getting h(r-h)=
由 jinjing
於 2011-08-15 16:44:33
所有跟帖:
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Sorry, It should be: (R+r-h)h=(R+r)^2-R^2-h^2,...
-jinjing-
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08/15/2011 postreply
17:33:49