I guess,cma's major is math, all answers are wrong in strict Mat

Be careful, only 5 is a real root, that means the other 3 roots are complex numbers.if we write

f(x)=a(x-2)(x-b) it should be f(f(x))=a^3(x-5)(x-p)(x-q)(x-r).p,q,r are complex numbers.If I'm right,b=3+p,a=2/(6-3p) so,f(0)=(12+4p)/(6-3p).It is easy to get q=h(p),r=g(p).p can take any complex number,if one of q,r is not real number.

I wish 15less say,"Ha,old gingir is hotter".

所有跟帖： 

• suppose you are right -15少- ♂ (740 bytes) () 07/16/2011 postreply 16:19:20

• great! -15少- ♂ (391 bytes) () 07/16/2011 postreply 17:08:12

• Sir,b is comlex number,you are too... -jinjing- ♀ (97 bytes) () 07/16/2011 postreply 18:57:01

• Let's skip this...... though a little competition is good. Jing -亂彈- ♂ (0 bytes) () 07/17/2011 postreply 18:07:29

• (cont), maybe you can post some new problems. -亂彈- ♂ (0 bytes) () 07/17/2011 postreply 18:08:01

• yes, let's skip this...... it is becoming boring -15少- ♂ (0 bytes) () 07/18/2011 postreply 05:39:40

• 回複：suppose you are right -jinjing- ♀ (35 bytes) () 07/16/2011 postreply 19:47:45

• You are mystifying ... -15少- ♂ (1077 bytes) () 07/17/2011 postreply 02:41:26

• I'm sorry ,I said complex,is real complex, means not real. -jinjing- ♀ (356 bytes) () 07/19/2011 postreply 06:35:33

• Accept complex number. -wxcfan123- ♂ (651 bytes) () 07/17/2011 postreply 13:18:23

• Modification and confusion -wxcfan123- ♂ (750 bytes) () 07/17/2011 postreply 16:01:30

• Only smart people can confuse. -jinjing- ♀ (64 bytes) () 07/19/2011 postreply 07:34:07