I pointed out your error. If you do not agree, please justify.
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A quadritic polynomial has two roots in complex domain. [elementary knowlege]
we know that f(x) is quadritic polynomial [given condtions]
so f(x) has two roots, which are b and 2 [2 is known root, given condtions]
we know also f(5) is a root of f(x) [f(f(5)) = 0, given condtions]
f(5) = 3a(5-b) [simple calcul according to your expression of f(x)=a(x-2)(x-b)]
so f(5) = 3a(5-b) = b, or f(5) = 3a(5-b) = 2 [elementary knowlege]
combined with b=3+p,a=2/(6-3p) [your conclusion]
I get p=-1,a=2/9，b=2 [I'm not strong in calcul, please point out my error, thanks!]
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my teacher told me: a real number is also a complex number, do you agree with him? or have you a mystified defintion of complex number?
[ZT] 我不明白您不肯承認我的解法處於什麽心理，不過我覺得挺沒意思的。---說了就走
