e 和 π 是超越數的證明:可從Lindemann–Weierstrass theorem得到
超越數 - 其中 e 是第一個被證明是超越數
所有跟帖:
• 對,但本質是e^x=sigma(x^n/n!) n from 0 to infinite. -jinjing- ♀ (0 bytes) () 02/26/2011 postreply 17:32:10
• 對,但本質是e^x=sigma(x^n/n!) n from 0 to infinite. -jinjing- ♀ (0 bytes) () 02/26/2011 postreply 17:32:10
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