標準答案 13/15

X vs. Y

X should attack by sea with probability 2/3 and by land with probability 1/3. The probability of a successful invasion is 13/15.

Both X and Y should choose their strategy randomly. Let x be the probability that country X attacks by sea. Let y be the probability that country Y defends by sea.

The probability of a successful invasion is :

f(x,y)=.8xy + x(1-y) + (1-x)y + .6(1-x)(1-y) = .8xy + x - xy + y - xy + .6 - .6x - .6y + .6xy = -.6xy + .4x + .4y + .6 .

Y is obviously going to try to minimize the probability of a successful attack. Taking the derivative of f(x,y) with respect to y yields:

-.6x + .4 = 0.

x=2/3.

Thus X should attack by sea with probability 2/3 and by land with probability 1/3. Y should also defend by sea with probability 2/3 and by land with probability 1/3. The probability of a successful invasion is -.6*(2/3)*(2/3) + .4*(2/3) + .4*(2/3) + .6 = 13/15.

 

- reference: from international high iq society's quiz level 4 out of 5

所有跟帖： 

• The writer is not qualified being my student. -jinjing- ♀ (283 bytes) () 11/18/2010 postreply 12:40:18

• The answer is right, but y=2/3 is wrong. The trick is that y be -jinjing- ♀ (58 bytes) () 11/19/2010 postreply 08:28:03