my explanation use a list of n+N-1 symbols, you break it into two segments as two sides of a n x N rectangle. I think once you arrive this point, you must have solved the problem. C(n+N-1, n)
my explanation use a list of n+N-1 symbols, you break it into two segments as two sides of a n x N rectangle. I think once you arrive this point, you must have solved the problem. C(n+N-1, n)
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