no

回答: 新題guest0072010-05-14 08:02:07

your answer is no better than this early one -
"此時,鴨子距岸3r/4。然後,鴨子沿直徑向岸遊3r/4=0.75r,同時狐狸須跑半個半徑為r的圓弧,即3.14r,抓鴨子。3.14r/0.75r > 4.鴨子先到岸而起飛。 "...

See optimal route and solution see 皆兄弟's answer 10-05-12 18:59:12 he is incorrec just because he though fox was not smart.

this is a old and 經典追逐,numbers in my question is duck's minimum velocity (0.21723363 to fox) - all other numbers (1/4 1/ PI+1...) is not right for obvious reasons.


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真不油墨,逗狐狸來回跑多好玩,哈哈。 -AnaZhang- 給 AnaZhang 發送悄悄話 AnaZhang 的博客首頁 (170 bytes) () 05/17/2010 postreply 14:45:26

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