no

來源: 2010-05-15 21:58:07 [舊帖] [給我悄悄話] 本文已被閱讀:

your answer is no better than this early one -
"此時,鴨子距岸3r/4。然後,鴨子沿直徑向岸遊3r/4=0.75r,同時狐狸須跑半個半徑為r的圓弧,即3.14r,抓鴨子。3.14r/0.75r > 4.鴨子先到岸而起飛。 "...

See optimal route and solution see 皆兄弟's answer 10-05-12 18:59:12 he is incorrec just because he though fox was not smart.

this is a old and 經典追逐,numbers in my question is duck's minimum velocity (0.21723363 to fox) - all other numbers (1/4 1/ PI+1...) is not right for obvious reasons.