Unless they are all smart enough to be trustworthy (in this case they all survive by missing all shots. Obviously none of them gets the lady, so pointless too), the survival probability is:
Case 1: %80 C dead first after A's 30% and B's 50%. A's survival probability here is then 80% * (3/3+3.5) = 36.9% and B is 80%-36.9%=43.1%
Case 2: %20 C survives the first round. B is then 100% dead. A's survival p here is 20%*30%=6% and C is 20%-6%=14%.
Overall, A survives 42.9%, B is 43.1% and C is 14%.
Ironic but truthful in life.
Case 1: %80 C dead first after A's 30% and B's 50%. A's survival probability here is then 80% * (3/3+3.5) = 36.9% and B is 80%-36.9%=43.1%
Case 2: %20 C survives the first round. B is then 100% dead. A's survival p here is 20%*30%=6% and C is 20%-6%=14%.
Overall, A survives 42.9%, B is 43.1% and C is 14%.
Ironic but truthful in life.
