回複：印度奧賽題（2星半）：無窮序列的最大值

來源: 火球魔法 於 2009-09-26 14:24:53 [] [博客] [舊帖] [給我悄悄話] 閱讀數 : (188 bytes)

(ln(n) * n)' = 1/(n^2) * (1 - ln(n))

which means when n = e = 2.718, the sequence is max. So it's the greater in a = 2^(1/2) and b = 3^(1/3).

a^6 = 8, b^6 = 9. So 3^(1/3).

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