回複:印度奧賽題(2星半):無窮序列的最大值

來源: 2009-09-26 14:24:53 [博客] [舊帖] [給我悄悄話] 本文已被閱讀:

(ln(n) * n)' = 1/(n^2) * (1 - ln(n))

which means when n = e = 2.718, the sequence is max. So it's the greater in a = 2^(1/2) and b = 3^(1/3).

a^6 = 8, b^6 = 9. So 3^(1/3).