i first calculate the probability a<=b,
(6+5/6+4/6+3/6+2/6+1/6)* 1/6 = 21/36
so it is same probablity for b<=c, c<=d
so (21/36) *(21/36)*(21/36) or (21/36)^3 is the answer
where is wrong?
i first calculate the probability a<=b,
(6+5/6+4/6+3/6+2/6+1/6)* 1/6 = 21/36
so it is same probablity for b<=c, c<=d
so (21/36) *(21/36)*(21/36) or (21/36)^3 is the answer
where is wrong?
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因為這三個事件不是獨立的。a《b就會影響b《c的選擇。
-sweetptt-
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12/29/2012 postreply
10:05:58
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thanks
-smallking-
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12/29/2012 postreply
10:13:25
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Sorry for posting the problem
-392-
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12/29/2012 postreply
10:16:42
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以後10年教兒子們,不能教錯吧,:)
-smallking-
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12/29/2012 postreply
10:19:33
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以後10年教兒子們? 你這麽年輕?
-392-
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12/29/2012 postreply
10:22:08
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幫我,撈一個
-smallking-
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12/29/2012 postreply
13:45:40
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