上麵是跟你開個玩笑。
如果把問題簡化一下,先擲兩次如何?也就是a<=b. 擲兩次出現a,b不同patten的個數是36(=6*6),滿足要求的pattern有 11,12,13,14,15,16, 22,23,24,25,26, 33,34,35,36, 44,45,46, 55,56, 66 共21個,所以概率是21/36. 是這樣嗎?
同樣的道理做a<=b<=c<=d...
上麵是跟你開個玩笑。
如果把問題簡化一下,先擲兩次如何?也就是a<=b. 擲兩次出現a,b不同patten的個數是36(=6*6),滿足要求的pattern有 11,12,13,14,15,16, 22,23,24,25,26, 33,34,35,36, 44,45,46, 55,56, 66 共21個,所以概率是21/36. 是這樣嗎?
同樣的道理做a<=b<=c<=d...
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