14/27

來源: newton123 於 2018-04-06 13:15:30 [] [博客] [舊帖] [給我悄悄話] 閱讀數 : (393 bytes)
回答: 求概率題，謝謝！ 由 niuniukoukou 於 2018-03-23 13:40:09

case 1, the two numbers Alan got are different, the chance for Beti is 1-4/6 * 4/6=5/9

case 2, the two numbers Alan got are identical, the chance for Beti is 1/6+1/6=1/3

The probability to get different two numbers for Alan is 5/6

The probability to get two identical numbers is 1/6

5/6 * 5/9 +1/6 * 1/3=25/54+1/18=28/54=14/27

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• case 2 is wrong. It is not 1/3. -yma16- ♂ 給 yma16 發送悄悄話 yma16 的博客首頁 (0 bytes) () 04/06/2018 postreply 20:46:30

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