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來源: 亂彈 於 2015-02-09 16:02:41 [] [博客] [舊帖] [給我悄悄話] 閱讀數 : (208 bytes)
回答: 數學不等式 11 由 魁北克人 於 2015-02-09 11:44:19

x^2+xy+y^2 = (z^3+y^3)/(x^2-xy+y^2)/3 + ... ,>= {(x+y)(y+z)(z+x)}^{1/3} (applying A-G inequality, simplify) , which is no less than 2 by A-G and xyz=1

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