p|n^3-1=(n-1)(n^2+n+1), since p is prime and n
So there are integers k and x such that p-1=kn and n^2+n+1=p x= knx + x. Take (mod n), x=1
p|n^3-1=(n-1)(n^2+n+1), since p is prime and n
So there are integers k and x such that p-1=kn and n^2+n+1=p x= knx + x. Take (mod n), x=1
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