[C(20,6)C(18,4)+...+C(20,9)C(18,1)+C(20,10)]/C(38,10)

來源: jinjing 於 2011-10-21 09:07:14 [檔案] [舊帖] [給我悄悄話] 閱讀數 : (0 bytes)

回答: [C(20,6)C(18,4)+C(20,7)C(18,3)+...+C(20,9)C(18,1)+C(20,10)]/C(38 由 jinjing 於 2011-10-21 09:05:05

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