剩下連續4米,輪種者輸;如果剩下2米加2米(被樹分開了),輪種者贏(無地可種).
所以你的假設 "3(k)+1,first lost" 首先就不對。因為從3(k+1)+1到3(k)+1,你不能保證3(k)+1是連續的。
剩下連續4米,輪種者輸;如果剩下2米加2米(被樹分開了),輪種者贏(無地可種).
所以你的假設 "3(k)+1,first lost" 首先就不對。因為從3(k+1)+1到3(k)+1,你不能保證3(k)+1是連續的。
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第一回合後方總能使一邊為連續的3X+1另一邊為連續的3T. X,T<=K
-jinjing-
♀
(195 bytes)
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03/18/2011 postreply
15:52:04
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you are right, I prove it again.
-jinjing-
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(283 bytes)
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03/20/2011 postreply
21:35:08
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you are way far from understanding the problem
-guest007-
♂
(37 bytes)
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03/21/2011 postreply
07:25:01
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Do you have answer? The key point is 整化.
-jinjing-
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(0 bytes)
()
03/21/2011 postreply
07:57:00
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