剩下連續4米,輪種者輸;如果剩下2米加2米(被樹分開了),輪種者贏(無地可種).
所以你的假設 "3(k)+1,first lost" 首先就不對。因為從3(k+1)+1到3(k)+1,你不能保證3(k)+1是連續的。
剩下連續4米,輪種者輸;如果剩下2米加2米(被樹分開了),輪種者贏(無地可種).
所以你的假設 "3(k)+1,first lost" 首先就不對。因為從3(k+1)+1到3(k)+1,你不能保證3(k)+1是連續的。
• 第一回合後方總能使一邊為連續的3X+1另一邊為連續的3T. X,T<=K -jinjing- ♀ (195 bytes) () 03/18/2011 postreply 15:52:04
• you are right, I prove it again. -jinjing- ♀ (283 bytes) () 03/20/2011 postreply 21:35:08
• you are way far from understanding the problem -guest007- ♂ (37 bytes) () 03/21/2011 postreply 07:25:01
• Do you have answer? The key point is 整化. -jinjing- ♀ (0 bytes) () 03/21/2011 postreply 07:57:00
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