回複:why P(notA*notB)=P(notA)*P(notB)?

來源: jinjing 2011-02-06 12:06:40 [] [舊帖] [給我悄悄話] 本文已被閱讀: 次 (311 bytes)
回答: why P(notA*notB)=P(notA)*P(notB)?wushuihe2011-02-06 08:46:37

P(notA)=P{aBcdef,abCdef,abcDef,abcdEf,abcdef}=.683

P(notB)=P{Abcdee,abCdef,AbcDef,abcdEf,abcdef}=.784

P(notA*notB)=P(abCdef,abcDef,abcdEf,abcdef}=.53.5=.683*.784

So,...

Why mony stars Q ,the anwser is the same,because the star show first, don't care the other stars,so....

所有跟帖: 

why P(abCdef,abcDef,abcdEf,abcdef}=.535? -wushuihe- 給 wushuihe 發送悄悄話 (0 bytes) () 02/06/2011 postreply 12:31:45

P(abCdef,abcDef,abcdEf,abcdeF,abcdef}=.681^2*.319+.681^3*.319+.. -jinjing- 給 jinjing 發送悄悄話 (219 bytes) () 02/06/2011 postreply 17:43:32

回複:P(abCdef,..,f}=.681^2*.319+.681^3*.319+..=.464=.681*.681 -jinjing- 給 jinjing 發送悄悄話 (0 bytes) () 02/06/2011 postreply 17:47:52

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