1/5(4*P(136/4,4)/P(137,137))
1/5(P(136/4)/P(137,137))
1/5(4*P(136/4,4)/P(137,137))
1/5(P(136/4)/P(137,137))
•
題看錯,...被任一人(除孔明)得的概率算式如下:
-jinjing-
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12/19/2010 postreply
13:37:19
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