A silly solution

Let x be the number of first part. From wrong:right = 1:2, we know x = (3^m)y, m=1,2,3,..., y=1,2,3,... From x+16 wrong:right = 1:3, we know 4|(x+16), therefore, x = (3^m)(4^n)z. From x+16 <= 50, we know m=n=1, z=1 or 2. ==> x=12 or 24. ==> these 16 wrong:right = 3:13 or 2:14, left=22 or 10.

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• 回複：A silly solution -jinjing- ♀ (46 bytes) () 10/25/2010 postreply 12:03:54