5張FULLHOUSE中隻有2種點不同,共有C(13,2)P(2,2),AAAKK,AAKKK是不同的,所以乘P(2,2),考慮到花色乘C(4,3)C(4,2)
概率為C(13,2)P(2,2)C(4,3)C(4,2)/C(52,5)=0.001440576
5張FULLHOUSE中隻有2種點不同,共有C(13,2)P(2,2),AAAKK,AAKKK是不同的,所以乘P(2,2),考慮到花色乘C(4,3)C(4,2)
概率為C(13,2)P(2,2)C(4,3)C(4,2)/C(52,5)=0.001440576
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