I got this transition. but,can you show what n equations are?

來源: 皆兄弟也 於 2010-09-14 08:41:16 [] [博客] [舊帖] [給我悄悄話] 閱讀數 : (333 bytes)
回答: Sorry,First term is not right. 由 jinjing 於 2010-09-13 17:47:58

a1 + b1x
=[（b2+c3b3+...+cnbn）a1 +（b2+c3b3+...+cnbn）b1x] /（b2+c3b3+...+cnbn）
= b1[（b2+c3b3+...+cnbn）a1/b1+（b2+c3b3+...+cnbn）x] /（b2+c3b3+...+cnbn）

where - should be corretted to +.

a2+b2x = a2+b2x
a3+b3x = (c3a3+c3b3x)/c3
...
an+bnx = (cnan+cnbnx)/cn

key is factor（b2+c3b3+...+cnbn）.

所有跟帖： 

• Thank you,you correct me the +,-.some where.Up is answer. -jinjing- ♀ 給 jinjing 發送悄悄話 (0 bytes) () 09/14/2010 postreply 10:09:35

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