i agree with you on this too, by eliminating the tricky part "無窮"in the original question.
當n成為有限整數後,每次換信封有更高的, 待值的推斷就不成立了,因為當你抽中最大的麵值時,換信封就損失很多。總的數學期望是一樣的,換或不換。
i.e. if 原題有兩個信封, 一個1元, 一個10元, 換不換。。。。
i agree with you on this too, by eliminating the tricky part "無窮"in the original question.
當n成為有限整數後,每次換信封有更高的, 待值的推斷就不成立了,因為當你抽中最大的麵值時,換信封就損失很多。總的數學期望是一樣的,換或不換。
i.e. if 原題有兩個信封, 一個1元, 一個10元, 換不換。。。。
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