near (400/Pi)*li, You are right.

回答: 輪子上一點移動多少距離?guest0072010-05-26 08:47:03

x=r(1-sint)
y=r(1-cost)
ds=2^.5r(1-cost)^.5dt,s=Intg(2^.5r(1-cost)^.5dt)from 0 to 2Pi= 8r, so (100/2Pi*r)*8r=(400/Pi)li.

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Agree with your answer -AnaZhang- 給 AnaZhang 發送悄悄話 AnaZhang 的博客首頁 (148 bytes) () 05/26/2010 postreply 18:36:36

Thanks, I did not know that word before -guest007- 給 guest007 發送悄悄話 (54 bytes) () 06/02/2010 postreply 09:14:07

請您先登陸,再發跟帖!