The question expects to see that when even V (fox) or V (cat) is at 4.60338811 times of V (duck), the duck can still free...
Cat or Fox at this speed (4.60338811 times of duck which is > 4.1415926 times), your answer is not related at all.
You have already figured out the right path before, maybe i jinjing-ed you...
answer is 鴨在半徑為x 的圓上與狐周旋於同一直徑遠端,然後沿切線遊完。 I belive you understand now.
Now i hope jinjing can understand as well - hehe
I mean vf is larger than that, the duck still can free
所有跟帖:
• 鴨在半徑為x 的圓上與狐周旋於同一直徑遠端,不可能. -jinjing- ♀ (170 bytes) () 05/14/2010 postreply 15:52:06
• 回複:鴨在半徑為x 的圓上與狐周旋於同一直徑遠端,不可能. -guest007- ♀ (64 bytes) () 05/15/2010 postreply 21:26:51