OK.Optimal policy:
1)If you sell y carts ,no $100,you buy all ,get the $100,and close door,OR sell all.
F(y)=[100xy+(100-y)(x*y+100)]/100.
y=(100x-100)/2x,you get Max.
2)If you sell y carts ,no $100,you buy till get $100,and then sell "0" all.OR sell all.
F(y)=[100xy+(100-y)(x*y+100)+(100-y)/2]/100
y=(100x-100)/2x,(Max)though y is the same,but gain is more.
Good luck.
回複:just delete that sentence
所有跟帖:
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回報的期待值是多少?
-guest007-
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05/10/2010 postreply
16:27:20
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F(y)=[100xy+(100-y)(x*y+100)+(100-y)/2]/100,y=(100x-100)/2x
-jinjing-
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05/10/2010 postreply
17:22:07
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算我懶
-guest007-
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05/10/2010 postreply
17:52:37
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1)x=2,F(75)=237.5,x=1,F(50)=125,x=.8,F(38)=110.2)x=2,F(75)=248.7
-Jinjing-
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05/10/2010 postreply
20:36:55
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謝謝- 還可以更高
-guest007-
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05/11/2010 postreply
06:53:37
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You want to peep?
-jinjing-
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05/11/2010 postreply
09:54:23
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peep tile win, then start sell
-guest007-
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05/12/2010 postreply
06:14:27