OK.Optimal policy:
1)If you sell y carts ,no $100,you buy all ,get the $100,and close door,OR sell all.
F(y)=[100xy+(100-y)(x*y+100)]/100.
y=(100x-100)/2x,you get Max.
2)If you sell y carts ,no $100,you buy till get $100,and then sell "0" all.OR sell all.
F(y)=[100xy+(100-y)(x*y+100)+(100-y)/2]/100
y=(100x-100)/2x,(Max)though y is the same,but gain is more.
Good luck.
回複:just delete that sentence
所有跟帖:
• 回報的期待值是多少? -guest007- ♀ (0 bytes) () 05/10/2010 postreply 16:27:20
• F(y)=[100xy+(100-y)(x*y+100)+(100-y)/2]/100,y=(100x-100)/2x -jinjing- ♀ (42 bytes) () 05/10/2010 postreply 17:22:07
• 算我懶 -guest007- ♀ (137 bytes) () 05/10/2010 postreply 17:52:37
• 1)x=2,F(75)=237.5,x=1,F(50)=125,x=.8,F(38)=110.2)x=2,F(75)=248.7 -Jinjing- ♀ (111 bytes) () 05/10/2010 postreply 20:36:55
• 謝謝- 還可以更高 -guest007- ♀ (13 bytes) () 05/11/2010 postreply 06:53:37
• You want to peep? -jinjing- ♀ (0 bytes) () 05/11/2010 postreply 09:54:23
• peep tile win, then start sell -guest007- ♀ (6 bytes) () 05/12/2010 postreply 06:14:27