A fair dice is thrown repeatedly. Let Xn be the total sum of the first n throws. What is the probability that Xn is divisible by 13 as n goes to infinite.
Sum of dice throwing
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回複:Sum of dice throwing
-jinjing-
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03/28/2010 postreply
10:06:41
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回複:Cancel my anwser,It seems 1/13
-jinjing-
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03/28/2010 postreply
10:21:44
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回複:回複:Cancel my anwser,It seems 1/13
-crazy_math-
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03/29/2010 postreply
06:31:08
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Do my best (圖)
-Jinjing-
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03/29/2010 postreply
12:47:51
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P0 = (P12 + P11 + P10 + P9 + P8 + P7) / 6
-空指針異常-
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03/31/2010 postreply
10:50:20
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?
-jinjing-
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03/31/2010 postreply
17:30:00
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另一種解法
-空指針異常-
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03/31/2010 postreply
11:53:24
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oops,回錯貼了,應該是knight jump,版主幫刪了吧
-空指針異常-
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03/31/2010 postreply
11:56:31
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The problem is not clear.
-亂彈-
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03/30/2010 postreply
18:30:30
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回複:The problem is not clear.
-jinjing-
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03/30/2010 postreply
20:32:58