仔細再想,偶數也可二次完成。
1. at A city, 配 (n-2)/2 對,餘二根孤線。
2. at B city, 找出對子和二根孤線。
3. at B city, 連接對子和一根孤線成一長線,(見上貼), 餘一根孤線。
4. at A city, 先找出那一根孤線,然後再解(見上貼)。
春節快樂!!
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哦, you have already done that.
-guest007-
♀
(19 bytes)
()
02/14/2010 postreply
13:07:28
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回複:哦, you have already done that.
-cowgg-
♂
(479 bytes)
()
02/18/2010 postreply
17:34:29
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