仔細再想,偶數也可二次完成。
1. at A city, 配 (n-2)/2 對,餘二根孤線。
2. at B city, 找出對子和二根孤線。
3. at B city, 連接對子和一根孤線成一長線,(見上貼), 餘一根孤線。
4. at A city, 先找出那一根孤線,然後再解(見上貼)。
春節快樂!!
• 哦, you have already done that. -guest007- ♀ (19 bytes) () 02/14/2010 postreply 13:07:28
• 回複:哦, you have already done that. -cowgg- ♂ (479 bytes) () 02/18/2010 postreply 17:34:29
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