given the right triangle, as stated in the problem,
two right sides A and B, having
A^2 + B^2 = 10^10
and the area is,
A*B/2=6*10/2
There is no solution for A and B in real domain.
Please see the details inside.
所有跟帖:
• 回複:WELL DONE -Kingoftheworld- ♂ (0 bytes) () 09/20/2009 postreply 20:45:13
• 回複:Please see the details inside. --閑雲野鶴-- ♂ (91 bytes) () 09/21/2009 postreply 07:59:05