方程組:
(1) Wp=T+Wx;
(2) 2/5Wx+Wb/2=Tcos45
方程組解:
T=(2/5Wp+Wb/2)/(1+cos45)
answer is:T=T=(2/5Wp+Wb/2)/(1+cos45)
所有跟帖:
• 錯了,應該為 T=(2/5Wp+Wb/2)/(2/5+cos45) -ghztomy- ♂ (0 bytes) () 03/29/2009 postreply 20:01:33
方程組:
(1) Wp=T+Wx;
(2) 2/5Wx+Wb/2=Tcos45
方程組解:
T=(2/5Wp+Wb/2)/(1+cos45)
• 錯了,應該為 T=(2/5Wp+Wb/2)/(2/5+cos45) -ghztomy- ♂ (0 bytes) () 03/29/2009 postreply 20:01:33
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