Sorry, seems to be
0.577 * (upper-bound currently known)
ExpectReturn(upper_bound) must be linear
ExpectReturn(upper_bound) = upper_bound * ExpectReturn(1)
Denote,
E(1, t) = ExpectReturn for test spend t for known upper 1
So
ExpectReturn(1) = max E(1,t), for all t in [0,1]
E(1,t) = t * (1-t) + ExpectReturn(0.9t)
= t * (1-t) + 0.9t ExpectReturn(1)
So
ExpectReturn(1) = max (t*(1-t) + t * 0.9ExpectReturn(1))
So, test at 0.5+0.45ExpectReturn give you the max, it is
(0.5 + 0.45 ExpectReturn)^2 = ExpectReturn
==>
ExpectReturn(1)=0.577
==>
ExpectReturn(m)=0.577m
回複:回複:讓人煩惱的禮金卡問題
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• 回複:回複:回複:讓人煩惱的禮金卡問題 -alladin- ♂ (681 bytes) () 01/11/2009 postreply 09:58:02