of the grass vs. the eating rate of a single cow.
As we know from the first condition, one cow in three days can finish grass grown on 1/3 of the total area.
Therefore, at the end of three days, 2 cows would have finished grass grown on 2/3 of the total area. What happends to the grass on the leftover - 1/3 of the total area during the 3 days? According to the second condition, it takes 2 cows another 3 days to finish. Therefore, the grass on the 1/3 area doubled during the three days. So we got the growth rate for the grass: they double every 3 days.
Now back to the final question. In three days 1 cow would finish eating grass grown on 1/3 of the area. What happends to the grass on the other 2/3 area? They double in 3 days! Compare to the starting day, the poor cow has even more grass to eat on the 3rd day. So it would never finish eating the grass.
One muggle
As we know from the first condition, one cow in three days can finish grass grown on 1/3 of the total area.
Therefore, at the end of three days, 2 cows would have finished grass grown on 2/3 of the total area. What happends to the grass on the leftover - 1/3 of the total area during the 3 days? According to the second condition, it takes 2 cows another 3 days to finish. Therefore, the grass on the 1/3 area doubled during the three days. So we got the growth rate for the grass: they double every 3 days.
Now back to the final question. In three days 1 cow would finish eating grass grown on 1/3 of the area. What happends to the grass on the other 2/3 area? They double in 3 days! Compare to the starting day, the poor cow has even more grass to eat on the 3rd day. So it would never finish eating the grass.
One muggle