都不難,OPEN 一個RECORDSET就可以了找到最大,再開一個找到最後。然後再開一個RECORDSET,顯示出每一個為0的,然後負值就可以了
都不難,OPEN 一個RECORDSET就可以了找到最大,再開一個找到最後。然後再開一個RECORDSET,顯示出每一個為0的,然後負值就可以了
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