又,抽樣次數為2n, 所以P(E1-->E2)恒等於1
從抽樣次數為2n, 怎樣能推出上麵恒等於1的結論?
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兩種卡,抽樣偶數次的情況下,如第一種卡被抽出偶數次
-15少-
♂
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08/05/2024 postreply
06:12:40
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