用正弦定理,三角形ABD中,AB=BD*sin30/sin100, 三角形BDC中,DC=BD*sin10/sin20, 易證sin30/sin100=sin10/sin20 (變換後積化和差, 或左=1/(2sin80)=/(2cos10), 右=sin10/(2sin10cos10)=1/(2cos10), 所以左=右)
用正弦定理,三角形ABD中,AB=BD*sin30/sin100, 三角形BDC中,DC=BD*sin10/sin20, 易證sin30/sin100=sin10/sin20 (變換後積化和差, 或左=1/(2sin80)=/(2cos10), 右=sin10/(2sin10cos10)=1/(2cos10), 所以左=右)
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