設角C= x。由正弦定理 AB/sin108= AD/sin36;DC/(sin?(72+x))= AD/sinx;
導至三角方程 sin(72+x)/sin108= sinx/sin36
顯然,解是x=36 = 角B。 AB= AC
設角C= x。由正弦定理 AB/sin108= AD/sin36;DC/(sin?(72+x))= AD/sinx;
導至三角方程 sin(72+x)/sin108= sinx/sin36
顯然,解是x=36 = 角B。 AB= AC
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