如圖,截取BE=BA,角BAE=角BEA=72度,又角ADE=72度,所以AE=AD,即角AED=72度,EC=DC-DE=BE-DE=BD=AD=AE, 所以AEC是等腰三角形,角ACB=72/2=36, 所以AB=AC
這個不難
所有跟帖:
• 高。我又是用三角解的。 -wxcfan123- ♂ (198 bytes) () 12/10/2023 postreply 14:27:36
如圖,截取BE=BA,角BAE=角BEA=72度,又角ADE=72度,所以AE=AD,即角AED=72度,EC=DC-DE=BE-DE=BD=AD=AE, 所以AEC是等腰三角形,角ACB=72/2=36, 所以AB=AC
• 高。我又是用三角解的。 -wxcfan123- ♂ (198 bytes) () 12/10/2023 postreply 14:27:36
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