thanks

來源: NIWbaby 於 2009-05-15 14:18:56 [] [舊帖] [給我悄悄話] 閱讀數 : (171 bytes)
回答: J2 question,please 由 NIWbaby 於 2009-05-15 08:39:14

Thanks, Your meaning is the same as my theory: j2 always follow j1. Once j1 completed the 2-yr service, j-2 does not have to completed the 2-yr service.

Am I right?

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• see this -frederick09- ♀ 給 frederick09 發送悄悄話 frederick09 的博客首頁 (552 bytes) () 05/15/2009 postreply 18:02:53

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