Another method

來源: monseigneur 於 2024-01-04 19:24:10 [檔案] [舊帖] [給我悄悄話] 閱讀數 : (27131 bytes)

回答: trial solution 由 monseigneur 於 2024-01-03 22:08:24

ABC is the corner cut out. CE and BD are parallel, so AC/AD=AE/AB, or AC*AB=AD*AE. So triangle ABC and ADE are of equal area. Let DF=AE/2, so area(DFG)=area(ADE)/2=area(ABC)/2. Cut along FG.