設FD=a, AF=ka. DC=10/a, AE=6/(ka).
由三角形EBC的麵積
(10/a - 6/(ka))(1+k)a = 8.
(10 - 6/k)(1+k) = 8
k=1.
設FD=a, AF=ka. DC=10/a, AE=6/(ka).
由三角形EBC的麵積
(10/a - 6/(ka))(1+k)a = 8.
(10 - 6/k)(1+k) = 8
k=1.
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