回複：Yes,you're right.

The problem I have with the solution is that the numbers of the terms of a
sequence are countable.  When you give me a term I can tell you its position (except the general expression). 
Where does x^x^...^x fit in the sequence?  But if you have a proof that you can break a general term into two infinite parts, just let me know.

Thank you very much.

所有跟帖： 

• 回複：回複：Yes,you're right. -jinjing- ♀ (205 bytes) () 01/16/2011 postreply 21:05:36

• I have to say I disagree with you. -yma16- ♂ (933 bytes) () 01/17/2011 postreply 09:51:33

• Thanks,but you are...,Newton was not clear,...100 more years Cau -jinjing- ♀ (287 bytes) () 01/17/2011 postreply 11:12:12

• When I can't your thanks, I check my answer again,my god...... -jinjing- ♀ (846 bytes) () 01/18/2011 postreply 12:31:15

• 回複：When I can't your thanks, I check my answer again,my god..... -yma16- ♂ (548 bytes) () 01/18/2011 postreply 14:22:39

• My friend,you'r great,a>e^(1/e) An is divergent. Why?Because... -jinjing- ♀ (127 bytes) () 01/18/2011 postreply 17:57:16

• thank you for the effort. This is the only -yma16- ♂ (450 bytes) () 01/20/2011 postreply 18:27:29

• Thanks,you are right. A old want to say....why the big one is no -jinjing- ♀ (302 bytes) () 01/21/2011 postreply 10:53:30

• I also found another example that taking a limit -yma16- ♂ (373 bytes) () 01/21/2011 postreply 17:42:54