很嚴格.從高著手可能簡單點.1)同底三角形頂點在(0,1),(0,0),(1,0)OR(1,1)有最大的高.2)定長的底以頂點在(0,1),(0,0),(1,0)OR(1,1)等腰三角形最大,3)得等邊三角形,得(3-squt3)/2.
很嚴格.從高著手可能簡單點.1)同底三角形頂點在(0,1),(0,0),(1,0)OR(1,1)有最大的高.2)定長的底以頂點在(0,1),(0,0),(1,0)OR(1,1)等腰三角形最大,3)得等邊三角形,得(3-squt3)/2.
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