Answer: A=pirr/arccos((r-h)/r))-(r-h)sqrt(2rh-h*h) where A is

badminton · 2010-04-20 09:11:29Z

Answer: A=pi*r*r/arccos((r-h)/r))-(r-h)sqrt(2rh-h*h) where A is簡介

來源: badminton 於 2010-04-20 09:11:29 [檔案] [舊帖] [給我悄悄話] 閱讀數 : (0 bytes)

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