This is a first hitting time problem of the symmetric random walk.
Assume the poor drunk guy starts from n steps far away from left door(n
since M(t) here is martingale, it's easy to show that E[tau]=n(100-n), here we have n=1, therefore E[tau]=99.
回複:another way to look at Quant麵試題:喝醉了(2.5星)
所有跟帖:
•
回複:回複:another way to look at Quant麵試題:喝醉了(2.5星)
-tianxing-
♂
(8 bytes)
()
10/24/2009 postreply
23:49:10