This is a first hitting time problem of the symmetric random walk.
Assume the poor drunk guy starts from n steps far away from left door(n
since M(t) here is martingale, it's easy to show that E[tau]=n(100-n), here we have n=1, therefore E[tau]=99.
回複:another way to look at Quant麵試題:喝醉了(2.5星)
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• 回複:回複:another way to look at Quant麵試題:喝醉了(2.5星) -tianxing- ♂ (8 bytes) () 10/24/2009 postreply 23:49:10