考慮
A(k+1)-A(k)
A(k) 去掉第k位後2008位數的奇數位減去偶數位的和。。
可以化為全部由0或1組成
本帖於 2009-07-08 17:46:53 時間, 由普通用戶 康MM 編輯
考慮
A(k+1)-A(k)
A(k) 去掉第k位後2008位數的奇數位減去偶數位的和。。
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