謝,K>=3,OK請看.m=2,不用做.原式可能有小筆誤.

M=2,OK,設K時OK, N(k)>=c(k,2)(k/2)^2/c(k,2), N(K+1)=[c(k+1,1)c(k,2)*(k/2)^2]/c((k+1),2)=...>=[(k+1)^2/2]^2. 證OK

M=K+1時時,有[a1,(a2,.....ak(+1))],[a2,(a1,......,ak(+1))],......,[a(k+1),(a1,...ak)],k+1種.c(k+1)

We have N(K+1)=[c(k+1,1)c(k,2)*(k/2)^2]/c((k+1),2)=[(k+1)*(k(k-1))/2]*[k*k/4]/[(k+1)*k/2]=k*k(k-1)/4

k>=3,We have >=[(k+1)^2/2]^2.